Right side 12tan^2 (x) from the trig identity sec^2x tan^2x = 1 sec^2x tan^2x 2tan^2x = 12tan^2x simp lying this sec^2x tan^2x So right side now matches left side 👍Click here👆to get an answer to your question ️ Find the general solution of the equation sec^2 2x = 1 tan 2x Join / Login Question Find the general solution of the equation sec 2 2 x = 1 − tan 2 x Easy Open in App Solution Verified by TopprYou can put this solution on YOUR website!

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Tan^2x-1/sec^2x=tanx-cotx/tanx+cotx
Tan^2x-1/sec^2x=tanx-cotx/tanx+cotx-Click here👆to get an answer to your question ️ If sec x sec^ 2x = 1 then the value of tan^ 8 tan^ 4 2tan^ 2x 1 will be equal to View 2103_jpg from CSC 300 at San Francisco State University tan 60 = y V 3/2 X 1/2 = V3, cot 60 = 1/2 V3 y V 3/2 3 sec 60 1 x 1/2 = 2, CSC 60 = r y = 2V3 V 372 3 Suppose the angle 0




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Giải các bài toán của bạn sử dụng công cụ giải toán miễn phí của chúng tôi với lời giải theo từng bước Công cụ giải toán của chúng tôi hỗ trợ bài toán cơ bản, đại số sơ cấp, đại số, lượng giác, vi tích phân và nhiều hơn nữa tan^2x=(sec^21) 怎么来的? 108;See the answer See the answer See the answer done loading
= 1 1/(cos^2 X) Sin^2 X = 1 Sin^2 X/cos^2 X = 1 tan^2 X =Sec^2 X UpvoteTanx = t Sec^2 x dx= dt So now it is, 1/ (1t)^2 dt This integral is given by 1/1t and t= tanx So, it is cosx/cosx sinx tanx = t Sec^2 x dx= dt So now it is, 1/ (1t)^2 dt This integral is given by 1/1t and t= tanx So, it is cosx/cosx sinx Integral of the function \frac {\cos ^2 x} {1\tan x} The identity, as you noted, is tan 2 x 1 = sec 2 x, for all values of x Rearranging, you absolutely get Rearranging, you absolutely get tan 2 x sec 2 x = 1
Solve for x tan (2x)=1 tan (2x) = 1 tan ( 2 x) = 1 Take the inverse tangent of both sides of the equation to extract x x from inside the tangent 2x = arctan(1) 2 x = arctan ( 1) The exact value of arctan(1) arctan ( 1) is π 4 π 4 2x = π 4 2 x = π 4 Divide each term bySec^2(2x) = 1 tan (2x) 1 tan^2(2x) = 1 tan(2x) tan^2 (2x) tan (2x) = 0 tan(2x) tan (2x) 1 = 0 either tan (2x) = 0 = tan (0°) 2x = npi 0 or x= npi/2Found 2 solutions by ewatrrr, MathLover1 Answer by ewatrrr () ( Show Source ) You can put this solution on YOUR website!




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Ex 34, 8 Find the general solution of the equation sec2 2x = 1 – tan 2x sec2 2x = 1 – tan 2x 1 tan2 2x = 1 – tan2x tan2 2x tan2x = 1 – 1 tan2 2x tan2x = 0 tan 2x (tan2x 1) = 0 Hence We know that sec2 x = 1 tan2 x So, sec2 2x = 1 tan2 2x tan 2x = 0 taHi Simplifying the following (sec^2x csc^2x) (tan^2x cot^2x) tan^2x = sec^2x 1 cot^2x = csc^2x 1 (sec^2x csc^2x) (sec^2x 1 csc^2x 1)= 2An alternative method is to take `sec^2 x ` and replace it by `1/(cos^2 x)` Replace `1/(cos^2 x)` by `1 tan^2 x` (the basic formula of trigonometry `1tan^2 x = 1/(cos^2 x)` )



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Prove the following identities $$(\sec^2 x \tan^2x)(\csc^2 x \cot^2x) = 1 2 \sec^2x \csc^2 x \tag i$$ $$\frac{\cos x}{1\tan x} \frac{\sin x}{1\cot x} = \sin x \cos x \tag {ii}$$ For $(\mathrm i)$ , I initially tried simplifying what was in the 2 brackets but ended up getting 1 1Solve for x tan(2x)1=0 Add to both sides of the equation Take the inverse tangent of both sides of the equation to extract from inside the tangent The exact value of is Divide each term by and simplify Tap for more steps Divide each term in by Cancel the # sin^2x cos^2x = 1 # This is readily derived directly from the definition of the basic trigonometric functions #sin# and #cos# and Pythagoras's Theorem Divide both side by #cos^2x# and we get # sin^2x/cos^2x cos^2x/cos^2x = 1/cos^2x # # tan^2x 1 = sec^2x # # tan^2x = sec^2x 1# Confirming that the result is an identity




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The points labelled 1, Sec(θ), Csc(θ) represent the length of the line segment from the origin to that point Sin(θ), Tan(θ), and 1 are the heights to the line starting from the xaxis, while Cos(θ), 1, and Cot(θ) are lengths along the xaxis starting from the origin 1tanx*tan2x = sec 2x LS =1 (sin x/cos x)(sin 2x/ cos 2x) =1 (sin x/cos x)(2sin x* cos x)/ cos 2x) =12sin^2(x)/(cos 2x) ={cos(2x) 2sin^2(x)}/cos (2x)Free trigonometric identities list trigonometric identities by request stepbystep




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Tan(x y) = (tan x tan y) / (1 tan x tan y) sin(2x) = 2 sin x cos x cos(2x) = cos ^2 (x) sin ^2 (x) = 2 cos ^2 (x) 1 = 1 2 sin ^2 (x) tan(2x) = 2 tan(x) / (1Free trigonometric identities list trigonometric identities by request stepbystepRewrite sec(x) sec ( x) in terms of sines and cosines Rewrite tan(x) tan ( x) in terms of sines and cosines Multiply by the reciprocal of the fraction to divide by 1 cos(x) 1 cos ( x) Write cos(x) cos ( x) as a fraction with denominator 1 1 Cancel the common factor of cos(x) cos ( x)




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A)cot x b)csc x c)tan x d)sec x tan x Please help me ( calculusSo here guests first 10 2 X equal to zero Oh then two eggs plus one equal to zero for 10 2 X equal to zero The general solution is two times X equal to And by now we have to divide both sides by two So here we get X equals and by upon to where an element of said that is a interior So it is a general solution of 10 2 X equal to zeroAnswer to II Derivatives 1) x = 2Vi 2) v = (z* – 22 1)2 This problem has been solved!




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But it can not be achieved in the domain of the equality otherwise (tan^2)x and (sec^2)x at (sin^2)x=1 will not be defined Share Cite Follow answered Nov 19 '14 at 1121 DSinghvi DSinghvi 535 3 3 silver badges 16 16 bronze badges $\endgroup$ Add a comment 0 $\begingroup$Calculus 2, integral of (1tan^2x)/sec^2x, integral of cos(2x) How do you verify the equation is an identity?




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Trigonometric Simplification Calculator \square!X Now there are various ways to see it Of course it is easier knowing the standard identities and using them, but they all pretty much boil down to sin 2 x cos 2 x = 1, which is in turn another way of writing Pythagoras, and which will definitely help hereSolve and name all the solutions of x tan^2xsecx=1 *** LCDcos^2(x) 2cos^2(x)cos(x)1=0 2cos(x)1)(cos(x)1)=0 2cos(x)1=0 cos(x)=1/2 x=π/32πk, 5π/32πk, k=integer




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If f(2tanx/(1 tan2x)) = 1/2(1 cos2x)(sec2x 2tanx) then find f(x) Welcome to Sarthaks eConnect A unique platform where students can interact with teachers/experts/students to get solutions to their queriesSeparate fractions Rewrite tan(x) tan ( x) in terms of sines and cosines Multiply by the reciprocal of the fraction to divide by sin(x) cos(x) sin ( x) cos ( x) Convert from cos(x) sin(x) cos ( x) sin ( x) to cot(x) cot ( x) Divide sec2(x) sec 2 ( x) by 1 1 Rewrite sec(x) sec (Substitute the trigonometric identity `tan^2(x) = sec^2(x)1` Note This is the same as `1 tan^2(x) = sec^2(x)` `(tan^2(x))/(1tan^2(x)) = (sec^2(x)1)/(sec^2(x))` Express it into




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Sec^2xTan x=1 within 0,2pi) Given trigonometric equation is Sec ^ 2 x Tan x = 1 Interval 0 , 2 pi Sec ^ 2 x Tan x = 1 > ( 1 ) We know that Sec ^ 2 xAbout Press Copyright Contact us Creators Advertise Developers Terms Privacy Policy & Safety How works Test new features Press Copyright Contact us Creators 1 For the question, tan(2x)tanx = 1, I divided it by tanx, and got the solution as ( 2n 1) π 6 tan2x = cotx = tan(π 2 − x) So, 2x = nπ π 2 − x So, 3x = ( 2n 1) π 2 But the book solved using the formula of tan(2x), and got the solution as ( 6n ± 1) π 6 I can see that my solution has odd multiples of π / 2, which should be




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Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with stepbystep explanations, just like a math tutorGive number and explanaton 2 Determine the exact value of tan^1(sq root 3) with explanation 3 Determine exact value of cos(cos^1(19 pi)) with explanation 4 Determine the Math What is a simplified form of the expression sec^2x1/sin x sec x ?Yes, sec 2 x−1=tan 2 x is an identity sec 2 −1=tan 2 x Let us derive the equation We know the identity sin 2 (x)cos 2 (x)=1 ——(i) Dividing throughout the equation by cos 2 (x) We get sin 2 (x)/cos 2 (x) cos 2 (x)/cos 2 (x) = 1/cos 2 (x) We know that sin 2 (x)/cos 2 (x)= tan 2 (x), and cos 2 (x)/cos 2 (x) = 1 So the equation (i) after substituting becomes tan 2 (x) 1= 1/cos 2 (x)




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\\int \tan^{2}x\sec{x} \, dx\ > View Question Please Help Solution 3 Sec Maths Studypool Equation at the end of step 1 sec 2 x • (1 s 2 cxo) xtan 2 = 0 Step 2 Step 3 Pulling out like terms 31 Pull out like factors s 3 ec 3 x 2 o sec 2 x xtan 2 = x • (s 3 ec 3 xo sec 2 tan 2) Trying to factor a multi variable polynomial 32 Factoring s 3 ec 3 xo sec 2 tan 2Get stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us! 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